1.

The oxidation states of S atoms in S_(4)O_(6)^(2-) from left to right respectively are {:("OO"),("||||"),(O^(-)-S-S-S-S-O^(-)),("||||"),("OO"):}

Answer»

`+6, 0, 0, +6`
`+3, +1, +1, +3`
`+5, 0, 0, +5`
`+4, +1, +1, +4`

Solution :LEFT S atom : +2 each from `=O+4`
`+1` from `- O^(-)""+1`
0 from `-S""0/(+5)`


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