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The P.E. of a simple harmonic oscillator, when the particle is half way to its end point is : |
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Answer» `(2)/(3)E` `E=(1)/(2)m omega^(2)r^(2)` and potential energy `E_(P)=(1)/(2)m omega^(2)X^(2)` When `x=(r^(2))/(2)` then `E_(P)=(1)/(2)m omega^(2)(r^(2))/(4)` `IMPLIES""E_(P)=(E)/(4)` Correct choice is (b). |
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