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| 1. |
The P.E. of a spring is E_(P) when is stretched through 1cm. When stretched through 2 cm, ils P.E. is |
| Answer» Solution :`(U_(2))/(U_(1))=(x_(2)^(2))/(x_(1)^(2))impliesU_(2)=((2)^(2))/(1^(2))xxE_(P)=4E_(P)` | |