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The `P - V` diagram of a system undergoing thermodynamic transformation is shown in figure. The work done by the system in going from `A rarr B rarr C is 30 J` and `40 J` heat is given to the system. The change in internal energy between `A and C` is A. `10 J`B. `70 J`C. `84 J`D. `134 J` |
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Answer» Correct Answer - A Heat given `DeltaQ =40J` and work done `DeltaW = 30J` `implies DeltaQ=DeltaQ-DeltaW = 40-30 = 10J`. |
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