InterviewSolution
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InterviewSolution
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The paramagnetic behaviour of `B_2` is due to the presence ofA. 2 unpaired electrons in `pi_(n) MO`B. `2 unpaired electrons in `pi^(**) MO`C. 2 unpaired electrons in `sigma^(**)MO`D. 2 unpaired electrons in `sigma_(b)MO` |
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Answer» Correct Answer - A `B_(2)`(electrons=10) `sigma(1s)^(2),sigma^(**)(1s)^(2),sigma(2s)^(2),sigma^(**)(2s)^(2),pi(2p_(x))^(1),pi(2p_(y))^(1)` Thus paramagnetic behaviour of `B_(2)` is due to the presence of two unpaired electrons in `pi`-bonding molecular orbital. |
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