The particle executing simple harmonic motion has kinetic energy K_(0)cos^(2)omegat. The maximum values of the potential energy and the total energy are respectively :

The particle executing simple harmonic motion has kinetic energy K_(0)

1.	The particle executing simple harmonic motion has kinetic energy K_(0)cos^(2)omegat. The maximum values of the potential energy and the total energy are respectively :
Answer» `(K_(0))/(2)` and `K_(0)` `K_(0)` and `2K_(0)` `K_(0)` and `K_(0)` 0 and `2K_(0)`. Solution :Kinetic energy `=K_(0)COS^(2)omega t` When ` cos^(2)omega t=1` thenkinetic energy `=K_(0)` (MAXIMUM). Thus maximum value of potential energy `=K_(0)` Maximum value of total energy = maximumvalue of potential energy `=K_(0)` Correct choice is ( C ).

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The particle executing simple harmonic motion has kinetic energy K_(0)cos^(2)omegat. The maximum values of the potential energy and the total energy are respectively :

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