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The particles displacement in a wave is given by `y = 0.2 xx 10^(-5) cos (500 t - 0.025 x)` where the distances are measured in meters and time in seconds. NowA. wave velocity is `2 xx 10^(4)ms^(-1)`B. particles velocity is `2 xx 10^(4)ms^(-1)`C. initial phase difference is `(pi)/(2)`D. wavelength of the wave is `(80pi)m`

Answer» Correct Answer - A::D
Comparing with `y = A cos (omegat - kx)`
`omega = 500s^(-1), k = 0.025 m^(-1)`,
`v = (500)/(0.025) = 2 xx 10^(4)m//s , lambda = (2pi)/(0.025) = 80 pi m`
`y = A cos (omegat - kx)`


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