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    				| 1. | 
                                    The particular solution of the differential equation x dy+2y dx=0, then x=2, y=1 isA. xy = 4B. `x^(2)y=4`C. `xy^(2)=4`D. `x^(2)y^(2=4` | 
                            
| Answer» Correct Answer - B | |