The path difference between the two waves `y_(1)=a_(1) sin(omega t-(2pi x)/(lambda)) and y(2)=a_(2) cos(omega t-(2pi x)/(lambda)+phi)` isA. `(lambda)/(2pi)/phi`B. `(lambda)/(2pi)(phi+(pi)/(2))`C. `(2pi)/(lambda)(phi-(pi)/(2))`D. `(2pi)/(lambda)(phi)`

The path difference between the two waves `y_(1)=a_(1) sin(omega t-(2p

1.	The path difference between the two waves `y_(1)=a_(1) sin(omega t-(2pi x)/(lambda)) and y(2)=a_(2) cos(omega t-(2pi x)/(lambda)+phi)` isA. `(lambda)/(2pi)/phi`B. `(lambda)/(2pi)(phi+(pi)/(2))`C. `(2pi)/(lambda)(phi-(pi)/(2))`D. `(2pi)/(lambda)(phi)`
Answer» Correct Answer - b `y_(1)=a_(1)sin(omegat-(2pix)/(lambda))` `y_(2)=a_(2) sin(omegat-(2pix)/(lambda)+phi+(pi)/(2))` phase difference `=(omegat-(2pix)/(lambda)+phi+(pi)/(2))-(omegat-(2pix)/(lambda))=(phi+(pi)/(2))` path difference `=(lambda)/(2pi)xx`phase differance` =(lambda)/(2pi)(phi+(pi)/(2))`

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The path difference between the two waves `y_(1)=a_(1) sin(omega t-(2pi x)/(lambda)) and y(2)=a_(2) cos(omega t-(2pi x)/(lambda)+phi)` isA. `(lambda)/(2pi)/phi`B. `(lambda)/(2pi)(phi+(pi)/(2))`C. `(2pi)/(lambda)(phi-(pi)/(2))`D. `(2pi)/(lambda)(phi)`

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