The path of a projectile is given by the equation y = ax – bx^(2), where a and b are constants and x and y are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively.

The path of a projectile is given by the equation y = ax – bx^(2), w

1.	The path of a projectile is given by the equation y = ax – bx^(2), where a and b are constants and x and y are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively.
Answer» `(2A^2)/(B), tan^(-1) (a)` `(b^2)/(2a), tan^(-1) (b) ` `(a^2)/(b), tan^(-1) (2B)` `(a^2)/(4B) , tan^(-1) (a)` Answer :D

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The path of a projectile is given by the equation y = ax – bx^(2), where a and b are constants and x and y are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively.

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