InterviewSolution
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InterviewSolution
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The path of one projectile as seen by an observer on another projectile is a/an:A. straight lineB. parabolaC. ellipseD. circle |
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Answer» Correct Answer - a We know that `x=(u cos theta)t and y =(u sin theta)t-1/2"gt"^(2)` Let `x_(2)-x_(1)=(u_(1)cos theta_(1)-u_(2)cos theta_(2))t=X` `y_(2)-y_(1)=(u_(1)cos theta_(1))t-1/2"gt"^(2)-(u_(2)cos theta_(2))t+1/2"gt"^(2)` `=(u_(1)sin theta_(1)-u_(2)sin theta_(2))t=Y` `Y/X=((u_(1)sin theta_(1)-u_(2)sin theta_(2))t)/((u_(1)cos theta_(1)-u_(2)cos theta_(2))t)` `=(u_(1)sin theta_(1)-u_(2)sin theta_(2))/(u_(1)cos theta_(1)-u_(2)cos theta_(2))` =constant m(say) `Y=mX` It is equation of a straight line passing through the origin. |
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