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The PE of a 2 kg particle, free to move along x-axis is given by `V(x)=((x^(3))/(3)-(x^(2))/(2))J.` The total mechanical energy of the particle is 4 J. Maximum speed (in `ms^(-1)`) isA. `(1)/(sqrt2)`B. `sqrt2`C. `(3)/(sqrt2)`D. `(5)/(sqrt6)` |
Answer» Correct Answer - D | |