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The PE of a 2 kg particle,free to move along x- axis is given by V(x)=\lbrack x^3/3-x^2/2\rbrack J.Total mechanical energy of the particle is 4J.Maximum speed \lbrack in m/s\rbrack is?

Answer» The PE of a 2 kg particle,free to move along x- axis is given by V(x)=\lbrack x^3/3-x^2/2\rbrack J.Total mechanical energy of the particle is 4J.Maximum speed \lbrack in m/s\rbrack is?


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