1.

The PE of a certain spring when streched from natural length through a distance `0.3m` is `5.6J`. Find the amount of work in joule that must be done on this spring to stretch it through an additional distance `0.15m`.

Answer» Correct Answer - `(7)`
`5.6=1/2k(0.3)^2`
`W=1/2k[(0.3+0.15)^2-0.3^2]`
Solving to get: `W=7J`


Discussion

No Comment Found

Related InterviewSolutions