1.

The peak value of an alternating emf E given by `E=(E_0) cos omega t` is 10V and frequency is 50 Hz. At time `t=(1//600)s` the instantaneous value of emf isA. 10 VB. `5 sqrt(3) V`C. 5 VD. 1 V

Answer» Correct Answer - b


Discussion

No Comment Found

Related InterviewSolutions