1.

The percentage error in measuring the radius of a sphere is 1%. If S_(1) = percentage error in volume of the sphere, S_(2) = percentage error in surface area of the sphere, S_(3) = relative error in the diameter of the sphere then arrange S_(1) S_(2) S_(3)according to the values in ascending order

Answer»

`S_(3) S_(2) S_(1)`
`S_(1) S_(2) S_(3)`
`S_(2) S_(1) S_(3)`
`S_(3) S_(1) S_(2)`

ANSWER :A


Discussion

No Comment Found