The percentage of hydrolysis in 0.003 M aqueous solution of NaOCN is: – InterviewSolution

1.

The percentage of hydrolysis in 0.003 M aqueous solution of NaOCN is: (Ka for HOCN = 3.33 × 10−4 M)

Answer»

The percentage of hydrolysis in $0.003 M$ aqueous solution of $N a O C N$ is:

( $K_{a}$ for $H O C N$ = $3.33 \times 10^{- 4} M$ )

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