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The perimeter of a rectangle is 44 cm. If one of the two adjacent sides is 1.8 cm longer than the other, what are the lengths of the sides? |
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Answer» :• Perimeter of rectangle = 44 cm• One of the adjacent SIDE is 1.8 cm longer than other.☆ To find :• The Length• The Breadth☆ Solution :LET the breadth of the rectangle be xThan length of the rectangle will be x + 1.8Perimeter of rectangle = 2(length + breadth)⟼ 44 = 2(x + 1.8 + x)⟼ 44 = 2(x + x + 1.8)⟼ 44 = 2(2x + 1.8)⟼ 44 = 4X + 3.6⟼ 44 - 3.6 = 4x⟼ 40.4 = 4x⟼ 40.4/4 = x⟼ 10.1 = x∴ The Breadth (x) = 10.1 cmAnd, length (x + 1.8) = 10.1 + 1.8 = 11.9 cm★ Check :—Perimeter of rectangle = 2(L + b)→ 44 = 2(11.9 + 10.1)→ 44 = 2(22)→ 44 = 2 × 22→ 44 = 44Thus, both sides are equal.Hence checked ! |
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