The perimeter of a rectangle is 52cm. If its width is 2cm more than on

1.	The perimeter of a rectangle is 52cm. If its width is 2cm more than one-third of its length, find the dimensions of the rectangle.
Answer» Answer: Let the LENGTH of RECTANGLE be xcm. then breadth = 1/3x+2cm. A/Q 2 (L+B)=52. 2 (x+1/3x+2)=52 2 (4x/3+2)=52 2 (4x+6/3)=52 8x+12/3=52 8x+12= 52×3 (by CROSS multiplication). 8x+12=156 8x=156-12 8x=144. x=144÷8 x=18. therefore length of rectangle=18cm. and breadth=1/3×18+2 18/3+2=24/3 cm. =8cm. *hope* it *helps* *you* *MATE. PLEASE* *thank* *and* *mark* my *answer* as *brainliest. @ ANUSHA* ❤✌

The perimeter of a rectangle is 52cm. If its width is 2cm more than one-third of its length, find the dimensions of the rectangle.

Answer»

Answer:

Let the LENGTH of RECTANGLE be xcm.

then breadth = 1/3x+2cm.

A/Q

2 (L+B)=52.

2 (x+1/3x+2)=52

2 (4x/3+2)=52

2 (4x+6/3)=52

8x+12/3=52

8x+12= 52×3 (by CROSS multiplication).

8x+12=156

8x=156-12

8x=144.

x=144÷8

x=18.

therefore length of rectangle=18cm.

and breadth=1/3×18+2

18/3+2=24/3 cm.

=8cm.

hope it helps you MATE.

PLEASE thank and mark my answer as brainliest.