The perimeter of a rectangle is a+2ab +c, one of its side is a-5ab, Fi

1.	The perimeter of a rectangle is a+2ab +c, one of its side is a-5ab, Find the other side.
Answer» Answer: Step-by-step explanation: Draw the rectangle. LABEL the short sides 'a = 4' and the long sides 'b'. Label the interior (area) 'C'. The PERIMETER is 2a + 2b And area = a times b If the perimeter = twice the area 'C', the n the equation will look like this: 2a + 2b = 2C - - - Now to solve for side b (length 'L'): We know that a = 4. 2a + 2b = 2C and ab = C = 4b = C We need to redefine b in TERMS of C: b = C/4 Plug it back into the original: 2a + 2b = 2C 2(4) + 2(C/4) = 2C Expand: 8+C/2 = 2C Multiply through by 2 16 + C = 4C Subtract C 16 = 3C Divide by 3 16/3 = C Now plug C into the original ab = C 4b = 16/3 Divide by 4 b = 4/3 the length of side b = 4/3

The perimeter of a rectangle is a+2ab +c, one of its side is a-5ab, Find the other side.

Answer»

Answer:

Step-by-step explanation:

Draw the rectangle. LABEL the short sides 'a = 4' and the long sides 'b'. Label the interior (area) 'C'.

The PERIMETER is 2a + 2b

And area = a times b

If the perimeter = twice the area 'C', the n the equation will look like this:

2a + 2b = 2C

- - -

Now to solve for side b (length 'L'):

We know that a = 4.

2a + 2b = 2C and

ab = C = 4b = C We need to redefine b in TERMS of C:

b = C/4 Plug it back into the original:

2a + 2b = 2C

2(4) + 2(C/4) = 2C Expand:

8+C/2 = 2C Multiply through by 2

16 + C = 4C Subtract C

16 = 3C Divide by 3

16/3 = C Now plug C into the original

ab = C

4b = 16/3 Divide by 4

b = 4/3 the length of side b = 4/3