The perimeter of a rectangle is twice the sum of its length and width

1.	The perimeter of a rectangle is twice the sum of its length and width whileits area is the product of its length and width. Such that,Perimeter = 2(L + w) and Area = Lºw
Answer» <P>ANSWER: we are given that the perimeter (P) P=2(L+w) and P=46 where length is l and width is w we are also told that length is 2 more than twice width ⇒l=2w+2 ⇒P=2(2w+2+w)=2(3w+2)=6w+4 equating perimeters gives 6w+4=46 subtract 4 from both sides and divide by 6 ⇒6w=46−4=42 ⇒w=426=7←width ⇒l=(2×7)+2=16←length Step-by-step explanation:

The perimeter of a rectangle is twice the sum of its length and width whileits area is the product of its length and width. Such that,Perimeter = 2(L + w) and Area = Lºw

Answer»

<P>ANSWER:

we are given that the perimeter (P)

P=2(L+w) and P=46

where length is l and width is w

we are also told that length is 2 more than twice width

⇒l=2w+2

⇒P=2(2w+2+w)=2(3w+2)=6w+4

equating perimeters gives

6w+4=46

subtract 4 from both sides and divide by 6

⇒6w=46−4=42

⇒w=426=7←width

⇒l=(2×7)+2=16←length

Step-by-step explanation:

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The perimeter of a rectangle is twice the sum of its length and width whileits area is the product of its length and width. Such that,Perimeter = 2(L + w) and Area = Lºw​

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The perimeter of a rectangle is twice the sum of its length and width whileits area is the product of its length and width. Such that,Perimeter = 2(L + w) and Area = Lºw