The perimeter of a rectangular field is 628m.The length of the field e

1.	The perimeter of a rectangular field is 628m.The length of the field exceeds its width by 6m.Find the dimensions.
Answer» LET the breadth of the field be X m then LENGTH =( X + 6) m perimeter = 2 {X + (X+6)} = 2(2X+6) = 4X + 12 according to the question, 4X+ 12 = 628 4X = 628-12 4X = 616 X = 616/4 = 154 m breadth= 154 m then length = 154+6 = 160 m

The perimeter of a rectangular field is 628m.The length of the field exceeds its width by 6m.Find the dimensions.

Answer»

LET the breadth of the field be X m

then LENGTH =( X + 6) m

perimeter = 2 {X + (X+6)}

= 2(2X+6) = 4X + 12

according to the question,

4X+ 12 = 628

4X = 628-12

4X = 616

X = 616/4 = 154 m

breadth= 154 m

then length = 154+6 = 160 m