Saved Bookmarks
| 1. |
The perimeter of a school hall was 128 m. The length of the school hall was 38 m longer than the breadth. What was the area of the school hall? |
|
Answer» - The perimeter of a school hall was 128 m.The length of the school hall was 38 m longer than the breadth.To Find :- Area of the school hall = ?SOLUTION :- Let Breadth be 'b'. Then, the Length would be 'b + 38'.According to Question :- ⋙ Perimeter of REACTANGLE = 2(Length + Breadth)⋙ 128 = 2(b + 38 + b)⋙ 128 = 2(2b + 38)⋙ 128 = 4b + 76⋙ 128 - 76 = 4b⋙ 52 = 4b⋙ b = 52 ÷ 4⋙ b = 13 mHence, Breadth of rectangle = b = 13 mLength of rectangle = b + 38 = 13 + 38 = 51 mNow, let's find the area of rectangle :⋗ Area of rectangle = Length × Breadth ⋗ Area of rectangle = 51 × 13⋗ Area of rectangle = 663 m²Therefore,area of rectangle is 663 m². |
|