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The perimeter of a school hall was 128 m. The length of the school hall was 38 m longer than the breadth. What was the area of the school hall? |
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Answer» -Perimeter of a school hall = 128 mThe length of the school hall was 38 m longer than the BREADTH. To Find :-The area of the school hall.Analysis :-CONSIDER the breadth as a variable and then the length WOULD be 38 more than the length.Substitute the values accordingly in the formula of perimeter of rectangle.Once you GET the length and breadth substitute them in the formula of area of rectangle.Solution :-We know that,l = Lengthb = Breadtha = Areap = PerimeterLet the breadth be 'x'. Then the length would be x + 38.By the formula,Given that,Perimeter (p) = 128 mSubstituting their values,128 = 2(x+38 + x)128 = 2(2x + 38)128 = 4x + 764x = 128 - 764x = 52X = 13Breadth = 13 mLength = x + 38 = 13 + 38 = 51 mTherefore, the length and breadth are 51 m and 13 m respectively.By the formula,Given that,Length (l) = 51 mBreadth (b) = 13 mSubstituting their values,Area = 51 × 13Area = 663 m²Therefore, the area of the school hall is 663 m². |
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