1.

The perimeter of a square is 60 m, find :(i) its each side its area(ii) its new area obtained on increasing(iii) each of its sides by 2 m.

Answer»

Perimeter of a square = 60 m

(i) Perimeter of a square = 4 x side

60 m = 4 x side

60/4 = side 4

∴side = 15 m

(ii) Area of square = (side)² = (15 m)²

= 15 m x 15 m

= 225 m²

(iii) Increased each side = 2 m

Side of square = 15 m

New length of side = (2m + 15m)

= 17m

∴ New Area of square = (17m)² = 17m x 17m = 289 m²



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