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The perimeter of a square is 60 m, find :(i) its each side its area(ii) its new area obtained on increasing(iii) each of its sides by 2 m. |
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Answer» Perimeter of a square = 60 m (i) Perimeter of a square = 4 x side 60 m = 4 x side 60/4 = side 4 ∴side = 15 m (ii) Area of square = (side)² = (15 m)² = 15 m x 15 m = 225 m² (iii) Increased each side = 2 m Side of square = 15 m New length of side = (2m + 15m) = 17m ∴ New Area of square = (17m)² = 17m x 17m = 289 m² |
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