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                                    The perimeter of a triangle ABC right angled at C is 70 and the inradius is 6, then `|a-b|=`A. 1B. 2C. 8D. 9 | 
                            
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Answer» Correct Answer - A We know `Delta =sr=(70//2)xx6=210` `rArr (1//2)ab=210rArr ab=420` Now `(a+b)^(2)=(70-c)^(2)` `rArr a^(2)+b^(2)+2ab=4900-140c + c^(2)` `rArr c=(4900-2xx420)/(140)=29 " " [because a^(2)+b^(2)=c^(2)]` `rArr (a-b)^(2)=a^(2)+b^(2)-2ab=c^(2)-2ab=841-840=1`  | 
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