The perimeter of a triangle is 5a² + 3a - 1 and two of its sides are – InterviewSolution

1.	The perimeter of a triangle is 5a² + 3a - 1 and two of its sides are 2a - 5 + 7a² and 3a² +4 - a. Find the third side of the triangle.
Answer» LET the THIRD side be xAlq,5a2+ 3a - 1 = 2a + 5+7a2 + 3a2 +4A +x 5a2 + 3a -1 = 6a + 10 a2 +5+x5a2 10a2 + 3a - 6a -1 -5 = x-5a2 - 3a -6 = x

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