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The perimeter of a triangle is 60om and itssides are in the ratio 3:4:5 What is its area? |
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Answer» Answer: The area of triangle is 23100 m² Step-by-step explanation: According to the GIVEN ratios the ∆ ABc is a Scalene triangle The ratios of the Scalene triangle ∆ ABC = 3:4:5 Let the ratios of Scalene triangle ∆ABC be 3x:4x:5x Perimeter of the Scapene triangle ∆ ABC = 600 m Perimetre = Sum of all the sides : The sum of terms of ratio of the Scalene triangle 600 m = 3x+4x+5x 600m = 12x The sum of all the sides = 50 m Semi perimeter of ∆ ABC = Total perimeter of triangle /2 Semi perimeter = 50 m / 2 = 25 m Area of ∆ABC = √ 25*[ (25-3) (25-4) (25-5) ] Area of ∆ABC = √25*[ ( 22*21*20) ] So the area of triangle is 23100 m² |
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