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The perimeter of a triangle is 8-9y+6 and its 2 sides r 4-7y and 4+14 find the third side pls give step by step explanation |
| Answer» PERIMETER of the triangle = Sum of THREE sides= 8y2 – 9y + 4Sum of TWO sides = 3y2 – 5y + 4Y2 + 12= 7y2 – 5y + 12∴ (8y2 – 9y + 4) – (7y2 – 5y + 12)= 8y2 – 9y + 4 – 7y2 + 5y – 12= y2 – 4Y – 8Hence third side = y2 – 4y - 8 | |