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The perimeter of rectangle is 28m. if the ratio of its length to its width 5:2. what is its area? |
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Answer» let be the length and BREADTH no. be = 5x and 2xPerimeter of rectangle = 2( L +B ) = 28 Then, 2(5x + 2X) = 28 10x + 4x = 2814 x 4 = 28 x = 28 / 14 x = 2 put the value of x L = 5× 2 = 10 and B = 2 ×2 = 4Area of rectangle = ( L × B ) = 10 × 4 = 40 sq. km |
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