The perimeter of the rectangle whose length is 64 cm and a diagonal 80

1.	The perimeter of the rectangle whose length is 64 cm and a diagonal 80 cm is
Answer» Given We have given LENGTH of Rectangle which is 64cm One of Diagonal is given which is 80cm To Find we have to find the perimeter of Rectangle $\sf\huge\bold{\underline{\underline{{Solution}}}}$ We KNOW the formula to find out the perimeter of Rectangle Perimeter of Rectangle=2(length+ breadth) Formula for finding Diagonal D²=l²+b² b²= D²-l²---(1) Solving for p(perimeter) =>perimeter = 2l+2(√d²-l²) [from Equation 1] =>Perimeter of Rectangle= 2×64+2×√(80)²-(64)² =>perimeter of Rectangle= 128+2×√6400-4096 =>Perimeter of Rectangle= 128+2×√2304 =>Perimeter of Rectangle=128+2×48 =>Perimeter of Rectangle=128+96=224cm Extra information=> Perimeter is the total distance occupy by a solid 2D figure around its edge. Properties of Rectangle: A rectangle is a type of quadrilateral. Opposite sides are parallel & equal Sum of all INTERIOR angles makes 360° Diagonals bisects each other and both diagonals are of same length.

The perimeter of the rectangle whose length is 64 cm and a diagonal 80 cm is

Answer»

We have given LENGTH of Rectangle which is 64cm

One of Diagonal is given which is 80cm

we have to find the perimeter of Rectangle

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

We KNOW the formula to find out the perimeter of Rectangle

Perimeter of Rectangle=2(length+ breadth)

Formula for finding Diagonal

D²=l²+b²

b²= D²-l²---(1)

Solving for p(perimeter)

=>perimeter = 2l+2(√d²-l²) [from Equation 1]

=>Perimeter of Rectangle= 2×64+2×√(80)²-(64)²

=>perimeter of Rectangle= 128+2×√6400-4096

=>Perimeter of Rectangle= 128+2×√2304

=>Perimeter of Rectangle=128+2×48

=>Perimeter of Rectangle=128+96=224cm

Perimeter is the total distance occupy by a solid 2D figure around its edge.

Properties of Rectangle: