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The perimeters of two similar triangles are 30 cm and 20 cm respectively.If one side of the first triangle is 9 cm long, find the length of thecorresponding side of the second triangle. |
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Answer» The side of the other triangle corresponding to 12 CM side of the FIRST one will be 12 * 20/30 = 8 cm, since SIDES and perimeter are linear and also similarity is a linear relation. Triangle ABC has AB = 10, BC = 24, and AC = 26. The perpendicular bisector of AC INTERSECTS the extension of AB at O. |
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