The period of a pendulum whose suspension is stationary relative to the Earth's surface is 1.50 s. What will its period be, if it is placed in a car moving horizontally with an acceleration of 4.9 m//s^(2)?What will be the change in the pendulum's angle of equilibrium?

The period of a pendulum whose suspension is stationary relative to th

1.	The period of a pendulum whose suspension is stationary relative to the Earth's surface is 1.50 s. What will its period be, if it is placed in a car moving horizontally with an acceleration of 4.9 m//s^(2)?What will be the change in the pendulum's angle of equilibrium?
Answer» Solution :One should find the total acceleration with respect to the EARTH: `w=sqrt(a^(2)+G^(2))`. Then the PERIOD of the pendulum will be `T=2pisqrt(l//w)`. The equilibrium POSITION will be DEFLECTED from the vertical by an angle `varphi=arc tan""(a)/(g)`

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The period of a pendulum whose suspension is stationary relative to the Earth's surface is 1.50 s. What will its period be, if it is placed in a car moving horizontally with an acceleration of 4.9 m//s^(2)?What will be the change in the pendulum's angle of equilibrium?

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