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The period of a satellite in a circular orbit of radius `R` is `T`, the period of another satellite in a circular orbit of radius `4R` isA. 64hrsB. 32hrsC. 16 hrsD. 8 hrs |
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Answer» Correct Answer - B Radius of orbit of the first satellite `R_(1)=R` Time period of the first satellite T=4 hrs. and radius of orbit of second satellite =4r Time period of satellite is given by `T prop r^(3/2)` hence `(T_(2))/(T_(1))=((r_(2))/(r_(1)))^(3/2)=((4r)/r)^(3/2) =8` `T_(2)=8xx4=32 ` hours |
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