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The period of moon around the earth is 27.3 daysand radius of the orbit is 3.9 × 10^5 km.\mathrm{G}=6.67 \times 10^{-11} \mathrm{Nm}^{-2} \mathrm{kg}^{-2} , find the mass of the earth. |
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Answer» T = 2π √r^3/GM 27.3 = 2 * 3.14 √(3.84 * 10^5)^3/6.67 * 10^-11 * M or 2.73 * 2.73 = 2 * 3.14 * (3.84 * 10^5)^3/6.67 * 10^-11 * M or M = 2 * (3.14)^2 * (3.84)^3 * 10^15/3.335 * 10^-11 (27.3)^2 = 6.02 * 10^24 kg ∴ mass of earth si found to be 6.02 * 10^24 kg. |
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