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The period of oscillation of a simple pendulum is T in a stationary lift. It thelift moves upward with acceleration of 8g the time period will : |
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Answer» becomes T/2 When lift ASCENDS then apparent ACCELERATION is `g.=g+a=g+8g=9g` `:.""T.=2pi sqrt((l)/(g.))=2pi sqrt((l)/(9g))impliesT.=(T)/(3)` Correct CHOICE is (b). |
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