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InterviewSolution
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The period of oscillations of a magnetic needle in a magnetic field is 1.0 sec. If the length of the needle is halved by cutting it, the time perood will beA. `1.0 sec`B. `0.5 sec`C. `0.25 sec`D. `2.0 sec` |
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Answer» Correct Answer - B `T=2pisqrt(I/(MB))=2pisqrt((wl^(2)//12)/("Pole strength" xx2lxxB))` `:.T propsqrt(Wl)` `:.T_(2)/T_(2)=sqrt(w_(2)/w_(1)xxl_(2)/l_(1))=sqrt((w_(1)//2)/w_(1)xx(l_(1)//2)/l_(1))=1/2` `impliesT_(2)=T_(1)/2=0.5s` |
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