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The period of revolution of a planet around the sun is 8 times that of the earth. If the mean distance of that planet from the sun is r, then mean distance of earth from the sun isA. `r//2`B. `2r`C. `r//4`D. `4r` |
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Answer» Correct Answer - c `t_(2)=8, r_(2)=r, r_(1)?` `(T_(2))/(T_(1))=((r_(2))/(r_(1)))^(3//2)` `(8)^(2//3)=(r_(2))/(r_(1))` `4=(r_(2))/(r_(1))" "therefore" "r_(1)=(r)/(4).` |
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