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The period of revolution of planet A round from the sun is 8 times that of B. The distance of A from the sun is how many times greater then tht of B from the sun ?A. 2B. 4C. 3D. 5 |
Answer» Correct Answer - C As `T_(2) prop r^(3)` so `(T_(A)^(2))/(T_(B)^(2))=(r_(A)^(3))/(r_(B)^(3))` or `(r_(a))/(r_(B))=(T_(A))/(T_(B))^(2//3)=(8)^(2//3)=4 rarr r_(A)=4r_(B)` so `r_(A)-r_(B)=4r_(B)-r_(B)=3r_(B)` |
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