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The permittivity of free space epsi_0=8.86 xx 10^(-12) coulomb/N-m^2 and the permeability of the free space mu_0 = 1.26 xx 10^(-6) henry/metre.If c is the velocity of light in vacuum, the correct relation between mu^0,epsi_0 and c is |
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Answer» `mu_0c^2 = epsi_0` |
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