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The pH of `0.01M HCN` solution for which `pK_(a)` is 4 isA. `0.47`B. `1.2`C. `3.0`D. `4.0` |
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Answer» Correct Answer - C Given, `pK_(a) = 4` `:. K_(A) = 1xx 10^(-4)` `[H^(+)] = sqrt(K_(a) xx C) = sqrt(1xx 10^(-4) xx 0.01)` `=sqrt(10^(-6)) = 10^(-3)M` `pH =- log [H^(+)] =- log 10^(-3) = 3` |
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