1.

The pH of 10^(-2) M Ca(OH)_(2) is

Answer»

12
12.3
11.3
2

Solution :`[OH^(-)] = 2 xx 10^(-2)`
`pOH = LOG(2 xx 10^(-2)) = 1.6990`
`:. pH = 14 - 1.6990 = 12.3010`.


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