1.

The pH of a simple acetate buffer is given by pH = pK_(a) + log.(["Salt"])/(["Acid"]) K_(a) of acetic acid = 1.8 xx 10^(-5) If [Salt] = [Acid] = 0.1 M, the pH of the solution would be about

Answer»

7
4.7
5.3
1.4

Solution :`["SALT"] = 0.1 M, ["Acid"] = 0.1 M`
`K_(a) = 1.8 xx 10^(-5) , PH = -logK_(a) + log.(["Salt"])/(["Acid"])`
`= -log 1.8 xx 10^(-5) + log.(0.1)/(0.1) = -log 1.8 xx 10^(-5)`
`pH = 4.7`.


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