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The phase difference between the instantaneous Velocity and acceleration of a particle executing simple harmonic motion isA. ZeroB. `0.5 pi`C. `pi`D. `0.707 pi` |
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Answer» Correct Answer - B If `v=v_(0) sin omega t ` then `a=a_(0) cos omega t` `implies` phase difference `=(pi)/(2)=0.5 pi` |
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