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The phase difference between the voltage and the current in an AC circuit is `pi//4`. If the frequency is `50Hz` then this phase difference will be equivalent to a time ofA. `0.02s`B. `0.25s`C. `2.5 ms`D. `25 ms` |
Answer» Correct Answer - C Time difference `=T/(2pi)xxvarphi=((1//50))/(2pi)xx(pi)/4` `=1/400s=2.5 ms` |
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