InterviewSolution
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InterviewSolution
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The phase difference between two waves represented by `y_(1)=10 ^(-6) sin [100 t+(x//50)+0.5]m, y_(2)=10^(-6) cos[100t+(x//50)]m`where x is expressed in metres and t is expressed in seconds, is approximatelyA. 2.07 radiansB. 0.5 radiansC. 1.5 radiansD. 1.07 radians |
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Answer» Correct Answer - D `y_1=10^(-6) sin { 100 t + x/50 +0.5 }` `y_2=10^(-6) cos {100t+x/50}` `=10^(-6) sin { pi/2 + 100t +x/50}` Phase difference between `y_1` & `y_2 =pi/2 -0.5` =1.58-0.5 =1.08 radians |
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