1.

The photoelectric cut-off voltage in a certain experiment 1.5 V. What is the maximum kinetic energy of photoelectrons emitted ?

Answer»

Solution :Here `V_(0) = 1.5` V
`K_(max) = eV_(0) = 1.5 eV`
`= 1.5 xx 1.6 xx 10^(-19) J`
`K_(max) = 2.4 xx 10^(-19)J`


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