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The photoelectric cut-off voltage in a certain experiment 1.5 V. What is the maximum kinetic energy of photoelectrons emitted ? |
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Answer» Solution :Here `V_(0) = 1.5` V `K_(max) = eV_(0) = 1.5 eV` `= 1.5 xx 1.6 xx 10^(-19) J` `K_(max) = 2.4 xx 10^(-19)J` |
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