InterviewSolution
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InterviewSolution
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The photoelectric threshold wavelength of silver is `3250 xx 10^(-10) m`. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength `2536 xx 10^(-10) m` is `(Given h = 4.14 xx 10^(6) ms^(-1) eVs` and `c = 3 xx 10^(8) ms^(-1))`A. `~~0.6xx10^(6) ms^(-1)`B. `~~61xx10^(3) ms^(-1)`C. `~~0.3xx10^(6) ms^(-1)`D. `~~6xx10^(5) ms^(-1)` |
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Answer» Correct Answer - A::D `phi=1242/325=3.82 eV` `E=1242/253.6=4.89 eV` `K_(max)=E-phi=1.077 eV` `1/2mv_(max)^(2)=1.077xx1.6xx10^(-19)` `v_(max)=((2xx1.077xx1.6xx10^(-19))/(9.1xx10^(-31)))^(1//2)=0.6xx10^(6)m//s` |
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