1.

The photoelectric work function for a metal surface is 4.125 eV. The cut off wavelength for this surface is

Answer»

3000 `Å`
2062.5 `Å`
4125 `Å`
6000 `Å`

SOLUTION :`lambda_(0) = (hc)/(W_(0)) = (6.63 xx 10^(-34) xx 3 xx 10^(8))/(4.125 xx 1.6 xx 10^(-19)) m = 3 xx 10^(-7) m = 3000 Å`


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