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The photoelectric work function of potassium is 2.3 eV. If light having wavelength of 2800 A^@ falls on potassium , find the stopping potentail in volts. |
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Answer» SOLUTION :`K _(MAX) = E V_0, THEREFORE 2.1 e V = e V_0` or `V_0 = 2.1 V`. |
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